Tolong dong, nge-stak nih•ᴗ•
Jawab:
5
Penjelasan dengan langkah-langkah:
[tex]1 - qx - px^2 = 0\\\dfrac{1}{x^2} - \dfrac{q}{x} - p = 0 \to \dfrac{1}{x_1}+\dfrac{1}{x_2} = -1 = q\\\dfrac{1}{x^2} + \dfrac{1}{x} - p = 0 \\-p = - \dfrac{1}{x^2}-\dfrac{1}{x} = \dfrac{1}{x\cdot (-1)\cdot \tfrac{3}{2}x}\\\dfrac{1}{x^2}+\dfrac{1}{x} = \dfrac{2}{3x^2}\\\\\dfrac{1}{x^2}+\dfrac{3}{x} = 0\\\\1+3x = 0\to x^{-1} = -3\to x^{-2} = 9\\\dfrac{2}{3}x^{-2} = p = 3\cdot 2 = 6, q = -1\\\\\\\boxed{\boxed{p+q = 5}}[/tex]
[answer.2.content]
