(2×-3)(4×pankat dua(2)+6×+9)

TOLONGG GAISS MAU DIKUMPULLL

(2×-3)(4×pankat dua(2)+6×+9)

TOLONGG GAISS MAU DIKUMPULLL

PERKALIAN

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Penyelesaian yang sesuai dengan pertanyaan!

Solution :

= (2x - 3)(4x² + 6x + 9)

= 2x(4x²) + 2x(6x) + 2x(9) - 3(4x²) - 3(6x) - 3(9)

= 8x³ + 12x² + 18x - 12x² - 18x - 27

= 8x³ + 12x² - 12x² + 18x - 18x - 27

= 8x³ + 0 + 0 - 27

= 8x³ - 27

[tex]{ \green{ \boxed{ \boxed{ \sf{ {Answer \: by : AdhidMagelang}}}}}}[/tex]

[tex]\sf\blue{ ✧بِسْمِ اللّهِ الرَّحْمَنِ الرَّحِيْمِ✧}[/tex]

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[tex] \\ [/tex]

Rumus =

[tex](a - b)( {a}^{2} + ab + {b}^{2} = {a}^{3} - {b}^{3} \\ \\ [/tex]

Oke next langsung ke caranya yaa!

[tex](2x - 3)( {4x}^{2} + 6x + 9) = \\ [/tex]

[tex] = ( 2x ) {}^{3} - {3}^{3} \\ [/tex]

[tex] = {8x}^{3} - {3}^{3} \\ [/tex]

[tex] = {8x}^{3} - 27 \\ \\ [/tex]

[tex] \\ [/tex]

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